Brand _____ Volume 5.0 mL (% on label) _____% Molarity (M) of NaOH _____ M Initi

Question

Brand _____ Volume 5.0 mL (% on label) _____% Molarity (M) of NaOH _____ M Initial NaOH level in buret Final NaOH level in buret Volume (mL) of NaOH used Average volume (mL) Average volume in liters (L) Moles of NaOH used in titration (Show calculations.) _____ mole NaOH Moles of HC_2H_3O_2 neutralized by NaOH (Show calculations.) _____ mole HC_2H_3O_2 Molarity of HC_2H_3O_2 (Show calculations) _____ M HC_2H_3O_2. Grams of HC_2H_3O_2 (Show calculations.) _____ g HC_2H_3O_2 Percent (m/v) HC_2H_3O_2 in vinegar (Show calculations) _____ % HC_2H_3O_2

Explanation / Answer

1. 5%

2. 0.5M

3.

cNaOH=0.4977 M3.85mL=0.0019276 moles NaOH

Moles of NaOH used =0.00193 moles NaOH

Molarity of HC3H3O2= 0.001932 Moles

0.0019276moles =CH3COOH60.052 /1mole CH3COOH=0.11576 g

percentage = 0.11576g2.50g×100=5.647%

Trial1 Trial2 Trial3 0 0 0 3.8 4 3.8 3.8 4 3.8 Average=3.85mL

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