Please answer rest of questions including Moles of base used Writing a balanced
ID: 535095 • Letter: P
Question
Please answer rest of questions including Moles of base used Writing a balanced molecular equation And the entire second chart labeled trial 1,2,3 TITRATION: ACID-BASE DATA I. Preparation of Sodium Hydroxide Solution Amount of NaOH stock solution needed to prepare 300m of o5M solution. Show eakoulations. MIV ISO IL Standardization of Sodium Hydroxide Solution Trial 3 Trial 1 Trial 2 019 2.06a 2.019 Weight of KHP Oloi mol 01001 .0101mol Base buret reading, final Base buret reading, initial 8.69 mL o16mL Molarity of base Average Molarity AN Show calculations: L 225 L 0101 move s asnHP mol OIOoim Gl. 44 B .061 I moinHP 61 00 moles M mot Im 01 KH? mol oi oi M o10i moue) d.013 107Explanation / Answer
Unknown acid
Neutralization reaction,
2H+ (from acid) + 2NaOH --> 2H2O + 2Na+ (salt of acid)
Trial 1,
moles base = 0.4603 M x 38.11 ml = 17.54 mmol
moles acid = 17.54/2 = 8.77 mmol
molar mass = 1.03 x 1000/8.77 = 117.45 g/mol
Trial 1,
moles base = 0.4603 M x 37.55 ml = 17.28 mmol
moles acid = 17.28/2 = 8.64 mmol
molar mass = 1.01 x 1000/8.64 = 117.00 g/mol
Trial 1,
moles base = 0.4603 M x 37.58 ml = 17.30 mmol
moles acid = 17.30/2 = 8.65 mmol
molar mass = 1.00 x 1000/8.65 = 115.61 g/mol
average molar mass of unknown acid = 116.69 g/mol