Please answer this! Thank you Part 1: Effect of Ethanol Concentration As you com

Question

Please answer this! Thank you

Part 1: Effect of Ethanol Concentration As you complete these problems COPY the results into your lab notebook for use during your lab. You need to create 6 Dilutions of ethanol-NAD+ with a total volume of 5.8 mL each. You are provided with a 0.1% (V/v ethanol stock solution. [NOTE: Density of ethanol is 0.788 g/mL at 20 oC.] The concentration of NAD will remain at a constant 1.67 mM. Complete the following table based on the use of the information above to make the following mM concentrations of ethanol. (5.8 mL of total volume is used) (Give answers to 4 sigfigs): Volume Volume Volume Dilution Ethanol](mM) [NAD+](mM) Ethanol (HL)Stock Needed NAD+ (uL)Stock Needed Tris-HCl buffer (UL)Needed Dilution 1 13.10 1.67 1.67 Dilution 2 6.550 Dilution 3 3.275 1.67 Dilution 4 1.638 1.67 Dilution 5 0.8190 1.67 1.67 Dilution 6 0.4095

Explanation / Answer

Part 1.

Concentraion of ethanol stock = 0.1 x 0.788/0.0999 x 46.07 = 0.01712 M = 17.12 mM

Dilution #1, Volume ethanol stock needed = 4.8 mM x 5.8 ml/17.12 mM = 1.626168 ml 1626.1680 uL

Similarly others can be caluculated.

Volume NAD+ stock needed = 1 ul in all the cases

Part 2,

Dilution #1, NAD+ stock needed = 4.9 mM x 5.8 ml/10 mM = 2.842 ml = 2842.0000 uL

Similarly others can be calculated

Volume ethanol stock neede = 1 uL in all the cases

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