Part Microscale Wittig Synthesis of trans-9-(2-Phenylethenyl)anthracene obtain a

Question

Part Microscale Wittig Synthesis of trans-9-(2-Phenylethenyl)anthracene obtain a clean, dry 5-mL conical vial and a spin vane or a 10-mL Erlenmeyer flask and a stir bar. To the vial or flask add 100 mg of 9-anthraldehyde, 190 mg of triphenylphosphonium chloride and 15 mL of methylene chloride. Stir vigorously Cautiously add 5 drops of 50% NaO dropwise, being careful to avoid splattering. Str for 30 minutes. Add 1.0 mL each of methylene chloride and water and remove the spin vane; cap and shake vigorously. Remove the lower organic layer to a clean Erlenmeyer flask. Extract the aqueous layer remaining in the conical vial with another 1-mL portion of methylene chloride. Combine the organic layers and dry with anhydrous sodium su fate. With filter pipet, transfer the dry organic solution to a 10-mL Erlenmeyer flask that contains a boiling chip or stir bar. Rinse the drying agent with l mLof an addi itiona

Explanation / Answer

According to the given data, 47 drops will be 2ml in volume. Therefor by following simple maths as below we can calculate the volume of 5 drops.

47 drops=2ml

1drop=2/47 => 0.0425ml

5 drops= 0.0425x5 => 0.213 ml

i.e 5 drops will contains 0.213 ml of volume

Now given that density of 50% NaOH= 1.52g/ml

Density=Mass/Volume

From this equation we can calculate Mass=Density X Volume => 1.52 X 0.213 =>0.323 g

For calculating Number of moles=Weight/ Molecular mass

Molecular mass of NaOH is 40 and the Weight is calculated above(=0.323g)

Therefore Number of Moles=0.323/40 => 0.00808 moles

Hence, Number of millimoles=0.0808x1000 => 8.08 mmoles

There are 8 mmoles in 5 dropes of 50% NaOH

I Hope this helps.

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