Please explain and provide answer Consider the following system at equilibrium w

Question

Please explain and provide answer

Consider the following system at equilibrium where 11° 198 k, and Kc = 34.5, at 1.15x103 K. 2SO2(g) + O2(g) 2SO3(g) If the VOLUME of the equilibrium system is suddenly decreased at constant temperature The value of Ke A. increases. B. decreases. C. remains the same. The value of QcA. is greater than Kc B. is equal to Kc C. is less than Kc The reaction must:A. run in the forward direction to reestablish equilibrium. B. run in the reverse direction to reestablish equilibrium. C. remain the same. It is already at equilibrium The number of moles of O2 will:A. increase. B. decrease. C. remain the same.

Explanation / Answer

Since temperature is constant, Kc will be constant

We are decreasing volume here

In other words we are trying to increase pressure

so, according to Le Chatelier's principle,

Reaction will try to decrease the pressure

Hence it will move in a direction which have lesser gaseous molecules

Here product has less gaseous molecule

So equilibrium will move to right

Equilibrium moves to product side

Qc is smaller than Kc

Since the reaction moves in forward direction, number of moles of O2 will decrease

Answer:

C

B

A

B

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