Correct Significant Figures Feedback: Your answer 0.29 nol was either rounded di
ID: 546278 • Letter: C
Question
Correct Significant Figures Feedback: Your answer 0.29 nol was either rounded di different number of significant figures than required for this part if you nned this resulit for later calculation in this item, keep all the digits and round as the final step before submitin answer Part D What mass of PC, will be produced from the given masses of bom reactants? Express your answer to three significant figures and include the appropriate units Hints Value Ungts Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Conti Fundamentals of General, Organic, and Biological Chen McMurry/Ballantine/HoegerExplanation / Answer
Balanced reaction for production of PCl5 is
P4 + 10 Cl2 -----> 4 PCl5
as you didn't give the mass of reactants i am taking random value you follow the same procedure but careful in finding the excess reactant and limiting reactant and make sure you use limiting reactant to do calculation
assuming
16 g of chlorine
23 g of phosphorous
Molar mass of Chlorine = 71 g/mol
Molar mass of Phosphorous = 124 g//mol
No. of moles of Chlorine = 16 g / 71 g/mol = 0.225 moles
No. of moles of phosphorous = 23 g / 124 g/mol = 0.185 moles
for each mole of P4, 10 moles of Cl2 is required
so 0.185 moles of P4 is excess
for 0.225 moles of 0.225/10 = 0.0225 moles of P4 is required
so Cl2 is limiting reactant and P4 in excess
when we 0.225 moles of Cl2 reacts
No. of moles of PCl5 produced = 4 * 0.225 /10 = 0.09 moles of PCl5
Molar mass of PCl5 = 208.24 g/mol
Mass of PCl5 = No. of moles of PCl5 * Molar mass of PCl5 = 0.09 moles * 208.24 g/mol = 18.74 g
follow the similar procedure with the values you have but find the limiting reactant with your values and follow the procedure accordingly