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CHM 2430 FA2017 NH eit nudlophi l 9% HC-N: H,C F. CH Sa. Arrange these nucleophi

ID: 546685 • Letter: C

Question

CHM 2430 FA2017 NH eit nudlophi l 9% HC-N: H,C F. CH Sa. Arrange these nucleophiles in order of decreasing nucleophilicity? (0.5 pt, 0.125 pt each) CHs A. B. Ci D. CHs Sb. Arrange these nucleophiles in order of decreasing nucleophilicity? (0.5 pt, 0.125 pt each) B. HSe D. H2Te: 2 5c. Which statement(s) about nucleophiles is(are) NOT correct-circle it(them)? (0.25 pt) A. they are Lewis bases. B. they react with electrophilies at electron-deficient atoms C. they donate an electron pair to the electrophile to form a new covalent bond. they are all negatively charged. most have an unshared electron pair that is donated to the electrophile. D. E.

Explanation / Answer

C. CH3- > NH2- > OH- > F-, since Nulceophilicity decreases from left to right in periodic table

D. P(CH3)3 > CH3SH > CH3Cl, same reason as above

E. EtS- > EtO- > EtSH> EtOH, anions are powerful nucleophile than neutral

F. P(CH3)3 > N(CH3)3 > (CH3)2S > CH3OCH3

5a. -P(CH3)2 > (CH3)3S- > CH3S- > Cl-

5b. H2Te > H2Se> H2S> H2O, increases from top to botttom

5c. Option D is wrong, since Nucleophile are both neutral like H2O, NH3 etc., and charged like OH-, Cl- and carbanions (CH3-)