I keep getting [H+] = 3.162 x 10^-12 and [OH-] = 3.162 x 10^-3 but it says I am

Question

I keep getting [H+] = 3.162 x 10^-12 and [OH-] = 3.162 x 10^-3 but it says I am wrong, Help!! THANK YOU

10/24/17 o This is a Numeric Entry question / it is worth 12 points You have sof8 attempts remaining/ There is no attempt penalty 07 Question 2 points) a See page 749 What are the concentrations of hydrogen ion and hydroxide ion in household ammonia, an aqueous solution of NHg that has a pH of 1150? M 4th attempt Part 1 (1 point El Md See Periodic Table O See Hint What is the concentration of hydroxide ion in household ammonia, an aqueous solution of NHg that has a pH of 1150? x 10 M OH Part 2 (1 point) What is the concentration of hydrogen ion in household ammonia, an aqueous solution of NHs that has a pH of 1150? M Ht 3rd attempt

Explanation / Answer

H = 11.50
POH = 14-PH
     = 14-11.50 = 2.5
POH = 2.5
-log[OH^-] = 2.5
      [OH^-] = 10^-2.5
      [OH^-]   = 0.00316M = 3.16*10^-3 M
part-2
    PH = 11.5
    -log[H^+] = 11.5
        [H^+] = 10^-11.5
               = 3.16*10^-12M

But method is correct . no another method. in this proble Kw value exeed the 10^-14M .

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