Mapd If you were going to graphically determine the enthalpy The equilibrium con
ID: 559036 • Letter: M
Question
Mapd If you were going to graphically determine the enthalpy The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T r, for this reaction, what points would you plot? The data is shown in this table Number Number To avoid rounding errors, use three T(K) K 325 3.62 575 8.57 point 1 significant figures in the x values and four Number Numbersignificant figures in the y values. point 2 Determine the rise, run, and slope of the line formed by these points ise run slope Number Number Number What is the standard enthalpy of this reaction? Number J/molExplanation / Answer
We need to plot lnK on y axis and 1/T on x axis
K = 3.62
ln K = ln (3.62) = 1.28647
T = 325.0
1/T = 0.00308
point 1 is:
x = 0.00308
y = 1.28647
K = 8.57
ln K = ln (8.57) = 2.14827
T = 575.0
1/T = 0.00174
point 2 is:
x = 0.00174
y = 2.14827
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rise = (y1-y2) = 1.28647 - 2.14827 = -0.86179
rise = (X1-X2) = 0.00308 - 0.00174 = 0.00134
slope = rise/run
= -0.86179/0.00134
= -644.1908
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use
slope = - deltaHo/R
= -644.1908 = -deltaHo/8.314
deltaHo = 5356 J/mol
Answer: 5356 J/mol
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