Part B A 50.0-mL volume of 0.15 M HBr is titrated with 025 M KOH Calculate the p

Question

Part B A 50.0-mL volume of 0.15 M HBr is titrated with 025 M KOH Calculate the pH after the addition of 13.0 mL of KOH Express your answer numerically. Hints Part C 1.8 × 10-s) is titrated with 0 500 M HNO, Calculate the pH after the addition of 230 mL of HNO3 A 75 0 ml volum e of 0 200 M NH3 (Kb Express your answer numerically Hints Part D A52 0 m:L vol m e of 0 35 M CH3COOH (K,=1.8 x10 s) is ttrated with 0 40 Mr NaOEI Calculate the pH after the addition of 25 0 mL of NaOH Express your answer numerically Hints

Explanation / Answer

part B)

millimoles of HBr = 50 x 0.15 = 7.5

millimoles of KOH = 13 x 0.25 = 3.25

here millimoles of acid > millimoles of base.

[H+] = 7.5 - 3.25 / (50 + 13) = 0.0675 M

pH = -log (0.0675)

pH = 1.17

part B)

millimoles of NH3 = 75 x 0.2 = 15

millimoles of HNO3 = 23 x 0.5 = 11.5

NH3 + HNO3 ------------------> NH4+

15 11.5 0

3.5 0 11.5

pOH = pKb + log [salt / base]

= 4.74 + log [11.5 / 3.5]

pOH = 5.26

pH = 8.74

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