For the polycaprolactone with a monomer-to-initiator-to-catalyst ratio of 15 0:1
ID: 561929 • Letter: F
Question
For the polycaprolactone with a monomer-to-initiator-to-catalyst ratio of 150:1:1, what is the volume of tin catalyst that will be added to the reaction with 60 mL of caprolactone?
Answer in mL rounded to two decimal places, e.g. 1.00 (Do not write the units in your answer)
0.40
1. Calculate the moles of caprolactone in the reaction using the volumn, density, and molecular weight.
2. Divide the moles of caprolactone by 150 to determine the moles of tin catalyst.
3. Calculate the mL of tin catalyst using the moles, molecular weight, and density.
For the polycaprolactone with a monomer-to-initiator-to-catalyst ratio of 150:1:1, what is the volume of tin catalyst that will be added to the reaction with 60 mL of caprolactone?
Answer in mL rounded to two decimal places, e.g. 1.00 (Do not write the units in your answer)
Selected Answer:0.40
Response Feedback:1. Calculate the moles of caprolactone in the reaction using the volumn, density, and molecular weight.
2. Divide the moles of caprolactone by 150 to determine the moles of tin catalyst.
3. Calculate the mL of tin catalyst using the moles, molecular weight, and density.
Explanation / Answer
Ans : 0.40 mL
The ratio of monomer to initiator to catalyst is 150 : 1:1
This means that 150 mL caprolactone needs 1 mL of each initiator and catalyst.
So now 60 mL of caprolactone will require 60 / 150
= 0.4 mL of catalyst.