Map dfa Sapling Learning macmillan learning When the oxide of generic metal M is
ID: 563893 • Letter: M
Question
Map dfa Sapling Learning macmillan learning When the oxide of generic metal M is heated at 25.0 °C, only a negligible amount of M is produced. M102(s) M(s)+0,4) Go-286.5 kJ / mol When this reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium, include physical states, and represent graphite as C(s) What is the thermodynamic equilbrium constant for the coupled reaction? Number K=Explanation / Answer
The reaction for graphite to carbon dioxide
C + O2 ==== CO2 Gibbs = -393.5 KJ / mol, from a book
add with
MO2 ===== M + O2 Gibbs = 285.6 KJ / mol
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MO2 (s)+ C (s) + O2===== M (s)+ CO2 (g) + O2, remove the compounds that appear on both sides so
MO2 (s)+ C (s) ===== M (s)+ CO2 (g)
gibbs energy is = 286.5 - 393.5 = -107 KJ / mol
Temperature is 298.15 Kelvin
apply
G = - RT Ln Keq
-107 000 J / mol = - 8.314 J / k mol * 298.15 (ln Keq)
-107 000 J / mol / (- 8.314 J / k mol * 298.15 ) = 43.165 = ln Keq
Keq = exp(43.165) = 5.58 x 1018
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