Show calculations and be mindtul of signiticant bgures tor tull credit The follo
ID: 564953 • Letter: S
Question
Show calculations and be mindtul of signiticant bgures tor tull credit The following data were observed in an equivalent mass of an acid experiment. 1) Fill in the blanks (2 points each). Show all calculations for full credit volume Final volume Net volume NaOH molarity Acid mass 0.1000 M 0.2511g 34 Numerical value: 2) (3 points) How many moles of hydroxide ion were consumed in the titration? 3) (G points) How many moles of hydronium ion were available from the acid? 4) (4 points) What is the equivalent molar mass of the acid?Explanation / Answer
2)
Volume of NaOH consumed = 33.6ml - 0.2ml = 33.4ml
Moles of hydroxide(OH-) ions = (0.1mol/1000ml) × 33.4ml = 0.00334mol
3)
moles of hydroxide ions consumed = moles of Hydronium ions were available
Therefore,
moles of Hydronium ions(H3O+) available = 0.00334mole
4)
Moles of Hydronium ions = No of Equivalents
Equivalent molar mass = mass /No of Equivalents
Equivalent molar mass = 0.2511g/0.00334Eq = 75.18g/Eq
5)
Tartaric acid
If multiply by Equivalent molar mass by 2 the result is 150.18g/mol which is equal to molar mass of tartaric acid.