Please show steps thank you! Answer both questions it the pH 4.5 of a water at 2

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Please show steps thank you! Answer both questions
it the pH 4.5 of a water at 25°C contains 0.62 mg/L of carbonic acid. What is the [HCO,1 concentration(i moles/L or M)? (a) 104s (b) 10835 (c) 1074s (d) 1068s [H + ][HCOiL 10-635 A baghouse has 424 cloth bags arranged in parallel. The flow rate is 45 m3/s and the concentration of particles is 15 g/m3. The discharge regulatory limit is 24 mg/m3. A manufacturer claim the efficiency of its unit is 99.5%. (a) Calculate the mass rate of the particles removed (mg/s), and (b) determine if this baghouse effluent will meet the discharge limit. Q 45 m3/s C 15 g/m Q45 m'/s c=? ash

Explanation / Answer

Given pH= 4.5, pH= -log [H+], [H+]= 10(-4.5)= 3.16*10-5 M

Concentration of H2CO3, [H2CO3]= 0.62 mg/L, molar mass of H2CO3= 62 g/mole

Concentration of H2CO3 in terms of moles/L= 0.62*10-3 g/L/62 g/mole = 0.00001

Given [H+] [HCO3-]/[H2CO3]= 10(-6.35) , 10(-4.5)* [HCO3-]/ 0.00001= 10(-6.35),

[HCO3-]= 10(-6.35+4.5)*0.00001=1.412*10-7, =10(-6.85) ( D is the correct answer)

2. Feed flow rate= 45 m3/s, solids concentration = 15 g/m3, solids flow rate = feed flow rate* solids concentration = 45 m3/s* 15 g/m3= 675 g/s

removal efficiency is 99.5%, so particles of solids removed= 675*0.995 g/s =671.6 g/s

so solids carried along with the feed = 675-671.6 =3.4 g/s= 3.4*1000 mg/s= 3400 mg/s

flow rate out of feed= 45 m3/s, hence solids concentratino at the exit = 3400 mg/s/45 m3/s= 75.5 mg/m3

so the bag house is not meeting the standard of 24 mg/m3.

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