Consider this reaction data If you were going to graphically determine the activ

Question

Consider this reaction data If you were going to graphically determine the activation energy this reaction, what points would you plot? A products Number Number T(K) k(s 275 775 To avoid rounding errors, use at least three significant figures in all values. point 1:275 0.380 0.380 0.745 Number Number point 2: 775 0.745 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number 0.365 500 7.3× 10-4 What is the activation energy of this reaction? Number 0.006 J/ mol

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis
K = 0.38
ln K = ln (0.38) = -0.96758
T = 275.0
1/T = 0.00364


point 1 is:
x = 0.00364
y = -0.96758


K = 0.745
ln K = ln (0.745) = -0.29437
T = 775.0
1/T = 0.00129


point 2 is:
x = 0.00129
y = -0.29437


----------------------------------------------------------------------------
rise = (y1-y2) = -0.96758 - -0.29437 = -0.67321
rise = (X1-X2) = 0.00364 - 0.00129 = 0.00235
slope = rise/run
= -0.67321/0.00235
= -286.95703
----------------------------------------------------------------------------
use
slope = - Ea/R
= -286.95703 = -Ea/8.314
Ea = 2386 J/mol

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