For the isomerization of glucose-1-phosphate to glucose-6-phosphate, the G° = -7
ID: 575482 • Letter: F
Question
For the isomerization of glucose-1-phosphate to glucose-6-phosphate, the G° = -7.28 (correct?). [Express your answer in kJ/mol using 2 significant figures.] the tolerance is +/-2%
At 37°C and concentrations of 5 mM glucose-6-phosphate and 0.1 mM glucose-1-phosphate, the G = . [Express your answer in kJ/mol using 2 significant figures.] the tolerance is +/-2%
Under these differing conditions, the isomerization of G1P to G6P is spontaneous under the 25C or 37C?
Phosphoenolpyruvate
Delta G = 61.9
1,3-Bisphosphoglycerate
49.4
ATP AMP + PPi
45.6
Phosphocreatine
43.1
ATP ADP + Pi
30.5
Glucose-1-phosphate
20.9
PPi 2 Pi
19.2
Glucose-6-phosphate
13.8
Glycerol-3-phosphate
9.2
Explanation / Answer
A ----------> B
delta G rxn = delta G of B - delta G of A
glucose-1-phosphate ------------> glucose-6-phosphate
delta Grxn = -13.8 - ( -20.9) = 7.1 KJ/mol
From your given data ..i got this but actually
delta Grxn from glucose-1-phosphate ------------> glucose-6-phosphate is -7.28 KJ/mol
It means the delta G values u have given are incorrect
delta G = delta Go + RT lnQ
Q = [ glucose-6-phosphate ] / [ glucose-1-phosphate ] = 5 mm / 0.1 mm = 50
delta G = -7.28 KJ + (8.314*(37+273)* ln50 ) = -2.8 KJ
when delta G is negative the reaction is spontaneous ;
At 25C the delta G value is negative
So the reaction is spontaneous at 25 C (not at 37 C since delta G is +ve )