Part B: two questions worth 24 points. Clearly write the equation and show the s
ID: 579360 • Letter: P
Question
Part B: two questions worth 24 points. Clearly write the equation and show the steps for all questions 1) CO (g) + 2H2(g) CH3OH (I) (Te at 298K Use this reaction to answer questions A-C) A) (3 points) Calculate the entropy change for the reaction As J/mol. K, Sgi 130.7 J/mol .K, Sco197.6)/mol. K at 298K , glven the following: S cowp 126.6 (3 points) Calculate the enthalpy change for the same reaction Henn given the following: HRCH30H(I) =-238.7k J/mol , Hecote, =-110kJ/mol B) C) (3 points)Is this reaction spontaneous under these conditions? Justify by calculating Gonn . D) A reaction has a ge, 30.1k/mol. Calculate the value of the equilibrium constant at 298K.(3 points)Explanation / Answer
a.
dS = Sproducts - Sreactants
SRxn = (CH3OH) - (CO+2H2)
dS = (126.6) - (130.7+197.6)
dS = -201.7 J/molK
b)
HRxn = hproducts - Hreactants
HRxn = (CH3OH) - (CO+2H2)
HRxn = (-238.7) - (-110+0) = -128.7
c)
dG = dH - T*dS
if dG < 0, this is spontaneous
dG = -128.7 - T*(-201.7/1000)
since this is negativ ein entropy, it must be only possible at low temperatures
d)
dG = -RT*lnK
K = exp(-DG/(RT))
K = exp(-30100/(8.314*298))
K = 5.29*10^-6