Please help me solve these questions including Q1. Thank you. EXPERIMENT 4 DETER

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Please help me solve these questions including Q1. Thank you.

EXPERIMENT 4 DETERMINATION OF IRONID BY REDOX TITRATION LEARNING ORIECTIVES Trg'in furth" pnihiney in the uw of 1he burrtte and titninn technique" · alealatio THEORY la thie experinent you will dtermine the cenoontration f D o in anquee sohution v Dichromate is a strong oxidiaing agot in acidic solution. In the titration reaction, dichromate sons will redared ta chrwisD and aron l will be sacidized ta ronkI A redox indicator will e d to mark the andpoint the indicssor chenges color from green to violet blue The net iosic equation for the reaction ie Dichrosate has several udvantages whea used in redex titeutices, however, chromium waste ia tosie and mast be disposed of oppropristols TECHNIQUE VIDEOS TO WATCH Pipette Top loading balanc Analytical balance Welghing by diffeeence EXPERIMENTAL MATERIALS wash bottle, filled with deionized water 230-ml. beaker . weighing vial * glass funnel 200 mL vobumetrie flask 250ml. Erlenmeyer flask 25.00-mL volumetric pipette ring stand burette clamp white tile 50-mL burette · . bot plate 25 ml graduated cylinder · Page 1 of 8

Explanation / Answer

Q1. We are given with equation as 14H+ + Cr2O7^2- + 6Fe2+ --> 2Cr3+ + 6Fe3+ + 7H2O

We know that oxaidtion = loss of electrons and Reduction = gain of electrons.

So, looking at the equation, we see that H and O do not change their oxidation states. Cr changes from +6 to +3. Means Cr gains electrons. Also, Fe changes oxidation state from +2 to +3, means it loses electrons.

So, Oxidation half-reaction = Fe+2 ====> Fe+3

And reduction half-reaction = Cr2O7 2- =======> Cr3+

(One question at a time). Have a nice day!

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