Please help me solve the following question: I started by solving for the net cu
ID: 3163268 • Letter: P
Question
Please help me solve the following question:
I started by solving for the net current: dV=(7.3V)-(2.8V)=4.5V
Then I placed it into Ohm's Law: V=iR, rearranging the equation to become: Rt=V/i=(4.5V)/(2.9A)=1.55.
From there, I solved for 1.55=0.15 • 4+Rm and have yet to get the correct answer. I have listed my answer attempts below, please do not submit any repeated incorrect answer attempts:
Credit will be given to those who give correct, clear, detailed answers using the proper units and explaining their reasoning. Thank you!
Class Management I Help Homework 6 Begin Date: 2/26/2017 5:00:00 AM Due Date: 3/6/2017 11:59:00 PM End Date: 3/6/2017 11:59:00 PM (8%) Problem 7: The motor in a toy car is powered by four batteries in series, which produce a total emf of 7.3 V. The motor draws 2.9 A and develops a 2.8 V back emf at normal speed. Each battery has a 0.15 2 internal resistance Randomized Variables V 7.3 V Vb, 2.8 V I 2.9 A r 0.15 2 What is the resistance of the motor in 2? Grade Summary Deductions Potential 100% sino cos0 tano 7 8 9 Submissions HOME Attempts remaining: 5 4 5 6 cotano asino acos0 (0% per attempt detailed view 2 3 atan0 acotan0 sinh0 cosh0 tanh0 cotanh0 vo Degrees Radians BACKSPACE Submit Hint Hints: 5% deduction per hint. Hints remaining: 4 Feedback: 5% deduction per feedback.Explanation / Answer
Here ,
let the resistance of the motor is R
Using KVL
V - Vb = I * (R + 4r)
7.3 - 2.8 = 2.9 * (R + 4 * 0.15)
solving for R
R = 0.95 Ohm
the resistance of the motor is 0.95 Ohm