Problem 19.20 Calculate the current through each resistor in (Figure 1) if each
ID: 582648 • Letter: P
Question
Problem 19.20 Calculate the current through each resistor in (Figure 1) if each resistance R = 4.25 k? and V = 16.0 V . Part A Calculate the current through resistor a. Express your answer to three significant figures and include the appropriate units. Ia = 0.0132 A SubmitMy AnswersGive Up Incorrect; One attempt remaining; Try Again Part B Calculate the current through resistor b. Express your answer to three significant figures and include the appropriate units. Ib = 0.00376 A SubmitMy AnswersGive Up Incorrect; Try Again; 2 attempts remaining Part C Calculate the current through resistor c. Express your answer to three significant figures and include the appropriate units. Ic = 0.00565 A SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part D Calculate the current through resistor d. Express your answer to three significant figures and include the appropriate units. Id = SubmitMy AnswersGive Up Part E Calculate the current through resistor e. Express your answer to three significant figures and include the appropriate units. Ie = 0.00188 A SubmitMy AnswersGive Up Incorrect; Try Again; 4 attempts remaining Part F Calculate the current through resistor f. Express your answer to three significant figures and include the appropriate units. If = 2.32×10?3 A SubmitMy AnswersGive Up Correct Part G What is the potential difference between points A and B? Express your answer to three significant figures and include the appropriate units. |VAB| =
A0 R AExplanation / Answer
We can sum Ra+Rb and put them in parallel with Rc. This new resistance is Rx = R. This Rx is now in series with Rd, making a new Ry=R. This Ry is in parallel with Re, so the new resistance there is Rz=R. This is now in series with Rf, so
Rtot= 13/8*R.
V = 16.0V
R = 4.25 k
Vc = V-V (¹³R)R = V = 5/13*16 = 6.1538 V
Vb = Vc-Vc RyR = Vc-Vc (R)R = Vc = ²V = 2/13*16 =2.4615 V
Va = 0
Rtot = ¹³R = 13/8 * 4.25 =6906.25
A) Ia = Vb 2R = 2.4615 / 2/4.25x103 = 2.896 x 10-4 Amp............Ans.
B) Ib = Ia =2.896 x 10-4 Amp............Ans.
C) Ic = Vb R = 5.792 x 10-4 Amp............Ans.
D) Id = (Vc-Vb) R = 3.6923 / 4.25x103 = 8.687 x 10-4 amp........Ans.
E) Ie = Vc R =6.1538 /4.25x103 = 1.44 x 10-3 amp........Ans
F) If = (V-Vc) R = (16 - 6.1538) / 4.25x103 = 2.316 x 10-3 amp........Ans
G) Is already answered above.