An entertainer juggles balls while doing other activities. In one act, she throw

Question

An entertainer juggles balls while doing other activities. In one act, she throws a ball vertically upward, and while it is in the air, she runs to and from a table 5.40 m away at an average speed of 2.20 m/s , returning just in time to catch the falling ball.

-With what minimum initial speed must she throw the ball upward to accomplish this feat?

Express your answer with the appropriate units.

-How high above its initial position is the ball just as she reaches the table?

Express your answer with the appropriate units.

Explanation / Answer

Time to go & come to table = (5.40 x 2) / 2.20 = 4.90 sec

from initial to highest point time is half of total = 2.45 s

at highest point V = 0

So,
V = u - gt

u = gt = 9.8 x 2.45 = 24.01 m/s

for highest point

S = ut - 1/2 gt^2

S = (24.01 x 2.45) - 1/2 x 9.8 x (2.45)^2

S = 29.42 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects