Map The equation for ATP hydrolysis is H,O ATPADPP =-30.5 kJ/mol (a) Calculate A

Question

Map The equation for ATP hydrolysis is H,O ATPADPP =-30.5 kJ/mol (a) Calculate AG for ATP hydrolysis to rank the following conditions from most favorable to least favorable. Assume a temperature of 37.0 . R = 8.315 J/(mol·K). ATP hydrolysis most favorable ATP hydrolysis least favorable muscle: [ATP] = 8.1 mM: [ADP] = 0.9 mM: [PJ-8.1 mM brain: [ATP] = 2.6 mM: [ADP] 0.7 mM: [PJ-2.7 mM liver: [ATP] = 3.4 mM: [ADP] = 1.3 mM: [P] = 4.8 mM continued below.. (b) Calculate AG for ATP hydrolysis in liver at 20.0 . Use the liver concentrations from part a. Number kJ/ mol

Explanation / Answer

since deltaG = deltaGO+RT*lnQ

given deltaGo= -30.5 Kj/mole= -30.5*1000jmole,

for muscleQ= reaction coefficient = [ADP] [PI]/[ATP] = 0.9*10-3*8.1*10-3/8.1*10-3 = 9*10-4

deltaG= -30.5*1000+8.314*(37+273)*ln(9*10-4)= -48575.2 KJ/mole

2. for brain Q= 0.7*10-3* 2.7*10-3/(2.6*10-3)=0.73*10-3,

deltaG= -30.5*1000+8.314*310*ln(0.73*10-3)= -49115 J/mole

for liver, deltaG= -30.5*1000+8.314*310*ln ({1.3*10-3*4.8*10-3)/3.4*10-3)}=-47738.1 J/mole

the lower the value of Gibbs free energy change, the more is the favorable

hence the order of stability is brain>muscle >liver

at 20 deg.c for liver, deltaG=

-30.5*1000+8.314*293*ln ({1.3*10-3*4.8*10-3)/3.4*10-3)}=-45846 J/mole

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