See Figure 11-1. In the molecule shown: Ha would be [ Select ] [\"singlet\", \"d
ID: 587130 • Letter: S
Question
See Figure 11-1. In the molecule shown:
Ha would be [ Select ] ["singlet", "doublet", "triplet", "quartet"] .
Hb would be [ Select ] ["singlet", "doublet", "triplet", "quartet"] .
Hc would be [ Select ] ["singlet", "doublet", "triplet", "quartet"] .
Hd would be [ Select ] ["triplet", "quartet", "quintet", "septet"] .
He would be [ Select ] ["singlet", "doublet", "triplet", "quartet"]
See Figure 11-2. Which of the following is/are true about Hb? (multiple answers is possible)
it is split into a doublet by Ha
it is split into a doublet by Hb
it is split into a doublet by Hc
it is split into a triplet by Hc
it is split into a doublet by Hd
See Figure 11-3. [ Select ] ["Ha", "Hb", "Hc", "Hd", "He"] would have there farthest downfield shift, and
[ Select ] ["Ha", "Hb", "Hc", "Hd", "He"] would have the farthest upfield shift.
Figa11-1 He He CIHs Hd Fi l-a Ha Ad HeHeExplanation / Answer
In figure 11-1,
The Ha would be a singlet, since the CH3 is attached to oxygen and there are no nuclei to split the signal. Hb would be a triplet and Hc would be a triplet, Hd would be a septet and He would be a doublet (Using the n+1 rule, where n is the number of Hydrogen atoms attached to the near by covalently bonded carbon)
Figure 11-2,
Here, Hb can be split into a doublet by Ha. It is also split into a triplet by Hc
Figure 11.3,
The farthest upfield shift(lowest chemical shift value) will be produced by the He (The value will be around 0.9-1)