If anyone could answer this question for me it would be much appreciated! (b) Th

Question

If anyone could answer this question for me it would be much appreciated!

(b) The following tables give overall equilibrium constant data (log %) for the interaction of [Ni(H2O)]2 ions with pyridine (py) and 2,2-bipyridine (bipy) Table 2 Data for the interaction of [Ni(H2O)2 with pyridine (py) and 2,2-bipyridine (bipy) at 25°C Species [Ni(py)2(H20)4]* [Ni(py) (H2022 [Ni(py)]2 3.5 5.6 9.8 Species 6.9 [Ni(bipy)2(H20213.6 19.3 [Ni(bipy)(H2O)]* [Ni(bipy) (i) Give a reason for the successive decrease in log Kn as n increases for the bipy complexes (ii) Compare the data for pyridine and 2,2-bipyridine. Explain why the equilibrium constants for complexes formed with 2,2-bipyridine are significantly higher than the values for the analogous nickel-pyridine complexes (ii) Copper reacts with pyridine to form complexes up to [Cu(py)1 but reactions with 2,2-bipyridine only result in the formation of [Cu(bipy)(H2O)4]2+and [Cu(bipy)2(H2O)2]2+. Explain why the tris complex with 2,2'-bipyridine would not form for copper

Explanation / Answer

i) the successive decrease in logKn as we increase n for bipy complexes is due to the change in its geometry, adding a extra bipy would facilitate towards a conformational change in which equilibrium constant will tend to shift in opposite direction, resulting in a decrease of logKn.

ii) due to its tetrahedral shape , which is more easier to attain equilibrium at a much faster rate , bipy has higher equilibrium constant value.

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