A sample of SO3 is introduced i Solution You were right to change the mols to mo
ID: 602177 • Letter: A
Question
A sample of SO3 is introduced iExplanation / Answer
You were right to change the mols to molarity by mol/2.4 = M. H2 + I2 ==> 2HI Set up an ICE chart. initial: (H2) = 0.714/2.4 = (I2) = 0.984/2.4 = (HI) = 0.886/2.4 = Now do the reaction quotient = (HI)^2/(H2)(I2) = (0.369)^2/(0.2975)(0.410) = about 1.1 or so which means at equilibrium the reaction will have gone to the right. change: (HI)= +2y (H2) = -y (I2)= -y equilibrium: (HI) = 0.369+2y (H2) = 0.2975-y (I2) = 0.41-y Substitute equilibrium values into Keq and solve for y and add that back into the equilibrium set up to arrive at the final concns.