A sample of PbCO3. XPb (OH)2 was heated with excess sulfuricacid, yeilding PbSO4

Question

A sample of PbCO3. XPb (OH)2 was heated with excess sulfuricacid, yeilding PbSO4 (s), H2O (l), and C02 (g). If 2.280 g ofPbSO4 and 0.1104 g of CO2 were obtained, What is the value of X? A sample of PbCO3. XPb (OH)2 was heated with excess sulfuricacid, yeilding PbSO4 (s), H2O (l), and C02 (g). If 2.280 g ofPbSO4 and 0.1104 g of CO2 were obtained, What is the value of X?

Explanation / Answer

         PbCO3.xPb(OH)2 +(1+x)H2SO4 + heat -->(1+x)PbSO4 + (1+2x)H2O + CO2 Mole of CO2: 0.1104g/44g/mol =2.51*10-3(mol) Mole of PbSO4: 2.280g/303g/mol =7.525*10-3(mol) In reaction, ratio mole between PbSO4 and CO2 is (1+x) : 1 =>Use mole of CO2 to find mole of PbSO4, we have theequation: 2.51*10-3(1+x) = 7.525*10-3 => 1+x = 3 =>x = 2

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