Marble (calcium carbonate) reacts with hydrochloric acid solution to form calciu

Question

Marble (calcium carbonate) reacts with hydrochloric acid solution to form calcium chloride solution, water, and carbon dioxide. What is the percent yield of carbon dioxide if 2.91 g of the gas is collected when 10.9 g of marble reacts? Please explain, i can't get it right.

Explanation / Answer

First write the balanced chemical equation: CaCO3 + 2 HCl --> CaCl2 + H2O + CO2. Now solve for the theoretical yield: (10.4 g CaCO3 / 1) * (1 mol CaCO3 / 100.0869 g CaCO3) * (1 mol CO2 / 1 mol CaCO3) * (44.0095 g CO2 / 1 mol CO2) = 4.57 g CO2. Now find the percent yield: Percent Yield = (Theoretical / Actual) * 100 Percent Yield = (2.86 g / 4.57 g) * 100 Percent Yield = 62.5%

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