Part A: Identify the reactant that is a Brønsted-Lowry acid and the reactant tha
ID: 636158 • Letter: P
Question
Part A: Identify the reactant that is a Brønsted-Lowry acid and the reactant that is a Brønsted-Lowry base in each of the following:
CO32?(aq)+H2O?HCO3?(aq)+OH?(aq) Multiple Choice
NH3(aq)+H2O(l)?NH4+(aq)+OH?(aq) Multiple choice
CH3?COO?(aq)+H3O+(aq)?H2O(l)+CH3?COOH(aq) Multiple choice
D. H3O+ is the acid (proton donor); CH3?COO? is the base (proton acceptor).
Part B: Calculate the [H3O+] of each aqueous solution with the following [OH?]:
NaOH, 6.0×10?3M . Express your answer using two significant figures.
milk of magnesia, 1.2×10?5M . Express your answer using two significant figures.
aspirin, 2.4×10?11M . Express your answer using two significant figures.
seawater, 4.0×10?6M . Express your answer using two significant figures.
A. CO32? is the acid (proton acceptor); H2O is the base (proton donor). B. H2O is the acid (proton donor); CO32? is the base (proton acceptor). C. CO32? is the acid (proton donor); H2O is the base (proton acceptor). D. H2O is the acid (proton acceptor); CO32? is the base (proton donor).Explanation / Answer
1) CO32-(aq)+H2O..................> HCO3-(aq)+OH-(aq)
Brønsted-Lowry acid is a proton (H+) donor. A Brønsted-Lowry base is a proton (H+) acceptor.
so option
B. H2O is the acid (proton donor); CO32? is the base (proton acceptor). is the answer.
2)
NH3(aq)+H2O(l).....................> NH4+(aq)+OH-(aq)
option B. H2O is the acid (proton donor); NH3 is the base (proton acceptor).
answer.
3) CH3COO-(aq)+H3O+(aq)........................> H2O(l)+CH3COOH(aq)
here acetate ion accept proton from H3O+. so acetate ion act as base and H3O+ is acid.
option D. H3O+ is the acid (proton donor); CH3?COO? is the base (proton acceptor).
answer