Part A For a certa n reaction, K. : 9 ? x 10 and kr 8.87 M 2 . S i Calculate the

Question

Part A For a certa n reaction, K. : 9 ? x 10 and kr 8.87 M 2 . S i Calculate the value ofthe reverse rate consta, kr gr en thathe reverse reacton is of the same molecularity as the fo ward reac on. Express your answer with the appropriate units. Include explicit multiplication within units, for example to enterM 1 include - (multiplication dot) between each measurement View Available Hint s) X-10" kr : Value Units Submit Previoue Anewere X Incorrect: Try Again 5 attempts remaining Enter your answer using dimensions of rate constant units for third-order reaction. Part B For a different reaction, K 1 13 hr 899s i and k 79.7 1 Adding a catalyst increases the fon ard rate constant to 3.35x10 s . What is the new value of the re erse eaction constant, h Express your answer with the appropriate units. Include explicit multiplication within units, for example to enter M2s include (multiplication dot) between each measurement. a er adding catalyst? View Available Hintfs) Units Submit

Explanation / Answer

given , Equilibrium constant KC= 9.69*107= Kf/Kb, where Kf is rate constant for forward reaction and Kb is rate constant for backward reaction, given Kf= 8.87/M2.sec

Kb= Kf/KC= 8.87/(9.69*107)= 9.1*10-8/M2,sec

2. The addition of catalyst does not affect the equilibrium constant, But it increases the rate of forward as well s backward reactions

KC in the presence of catalyst= 1.13= Kf/Kb, Kf is given = 3.35*104/s

KB= 1.13/(3.35*104)= 3.37*10-5/sec

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