Using the information given, calculate the molality of eachsolution. (Assume the

Question

Using the information given, calculate the molality of eachsolution. (Assume the density of each solution is 1.0 g/mL.) (a) 22.7 g of benzene(C6H6) dissolved in 66.7 g of cyclohexane(C6H12)
_____________m

(b) 16.2 g of formic acid (HCOOH, found inants) dissolved in 100.0 g of water
__________ m

(c) 0.194 g of acetaldehyde(C2H4O, found as the product of ethanolmetabolism) dissolved in 25.0 g of water
_____________ m Using the information given, calculate the molality of eachsolution. (Assume the density of each solution is 1.0 g/mL.) (a) 22.7 g of benzene(C6H6) dissolved in 66.7 g of cyclohexane(C6H12)
_____________m

(b) 16.2 g of formic acid (HCOOH, found inants) dissolved in 100.0 g of water
__________ m

(c) 0.194 g of acetaldehyde(C2H4O, found as the product of ethanolmetabolism) dissolved in 25.0 g of water
_____________ m (a) 22.7 g of benzene(C6H6) dissolved in 66.7 g of cyclohexane(C6H12)
_____________m

(b) 16.2 g of formic acid (HCOOH, found inants) dissolved in 100.0 g of water
__________ m

(c) 0.194 g of acetaldehyde(C2H4O, found as the product of ethanolmetabolism) dissolved in 25.0 g of water
_____________ m

Explanation / Answer

      The molality of thesolution is defined as the number of moles of the solute dissolvedin one kilogram of the solvent.                                  molality= number of moles / 1 kg of solvent                                                =(numberof moles of solute x 1000) / weight of solvent (g)           a) number of moles of benzene = 22.7 / 78 =0.2910                                  molality of the solution = (0.2910 x 1000) / 66.7 = 4.3632m           b) number of moles of formic acid =16.2 / 46 = 0.3521                               molality of the solution = (0.3521 x 1000) / 100                                                                      =3.521m c) number of moles of acetaldehyde = 0.194 /44 =0.0044                         molality of the solution = (0.0044 x 1000) / 25                                                                =0.176364 m

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