Consider the following reaction Ni(CO)4(g) <--> Ni(s)+4CO(g) Kc=0.0309 A mixture
ID: 678397 • Letter: C
Question
Consider the following reaction Ni(CO)4(g) <--> Ni(s)+4CO(g) Kc=0.0309 A mixture of Ni(CO)4(g) and CO(g) each with a concentration of.800 M and an excess of Ni(s) were confined in a 1.0-L container at300K Which of the following is true? A) Kc changes to 0.51 B) some Ni(CO)4(g) decomposes to CO(g) and Ni(s) C) no change occurs since we are at equilirbrium D) Ni(s) is formed E) Ni(CO)4(g) forms until equilibrium is reached Consider the following reaction Ni(CO)4(g) <--> Ni(s)+4CO(g) Kc=0.0309 A mixture of Ni(CO)4(g) and CO(g) each with a concentration of.800 M and an excess of Ni(s) were confined in a 1.0-L container at300K Which of the following is true? A) Kc changes to 0.51 B) some Ni(CO)4(g) decomposes to CO(g) and Ni(s) C) no change occurs since we are at equilirbrium D) Ni(s) is formed E) Ni(CO)4(g) forms until equilibrium is reachedExplanation / Answer
Consider the following reaction Ni(CO)4(g) <--> Ni(s)+4CO(g) Kc=0.0309 A mixture of Ni(CO)4(g) and CO(g) each with a concentration of.800 M and an excess of Ni(s) were confined in a 1.0-L container at300K Which of the following is true? A) Kc changes to 0.51 B) some Ni(CO)4(g) decomposes to CO(g) and Ni(s) C) no change occurs since we are at equilirbrium D) Ni(s) is formed E) Ni(CO)4(g) formsuntil equilibrium is reached...................currently the reaction quotient, Qc = 0.84/0.8 =0.51 >0.0309.....this means there's too much product present andsome reactant needs to form at the expense of product so as toreduce the Qc down to the value of Kc