Part A Express the pH numerically. Part B What is the pH of the solution at thee
ID: 678765 • Letter: P
Question
Part A Express the pH numerically.Part B What is the pH of the solution at theequivalence point? Express the pH numerically.
Part B What is the pH of the solution at theequivalence point? Express the pH numerically.
Explanation / Answer
HCl + NaOH -> NaCl + H2O PART A n(NaOH) added = cv = 0.25 x 0.05 = 0.0125mol c(HCl) = n/v n(HCl) = cv = 0.2 x 0.1 = 0.02mol n(H+) = 0.02mol n(H+) remaining after adding NaOH = 0.02 - 0.0125 =0.0075mol Total volume of solution = 100 + 50 = 150mL c(H+) = n/v = 0.0075/0.15 = 0.05M pH = -log [H+] pH = -log (0.05) pH = 1.30 PART B As this is a titration of stong acid and strong base, atequivalence point, the pH will be approximately 7 So, the pH is 7.00 Hope this helps!