a ) Balancedchemical equation : HCl + NaOH -----------> NaCl + H2O Beforerxn 0.1 L * 0.2 M 0.05 L *0.250 M 0 = 0.02mols 0.0125 mols Afterrxn 0.02 mols - 0.0125mols 0 = 0.0075 mols [H+] = 0.0075 mols / 0.1L + 0.05 L = 0.05 M pH = - log ( 0.05 ) = 1.30 b ) At the equivalence point pH will be 7 ,coz it is a strong acid and strong base titration.