I recently took a quiz in orgo, and I have no clue why I got thisquestion wrong!
ID: 687718 • Letter: I
Question
I recently took a quiz in orgo, and I have no clue why I got thisquestion wrong!Chlorination of pentane gives a mixture of isomers having themolecular formula C5H11Cl. The percentage of 1-chloropentane is 16%. Assuming thesecondary hydrogens in pentane are equally reactive tomonochlorination, what is the percentage of 2-chloropentane in themixture?
A. 26% B. 56% C. 42% D. 28% E. 16%
I thought it was 16% because if there are 6 primary hydrogens and 6secondary hydrogens and the fact that they react at the samerate...but it's wrong...
Chlorination of pentane gives a mixture of isomers having themolecular formula C5H11Cl. The percentage of 1-chloropentane is 16%. Assuming thesecondary hydrogens in pentane are equally reactive tomonochlorination, what is the percentage of 2-chloropentane in themixture?
A. 26% B. 56% C. 42% D. 28% E. 16%
I thought it was 16% because if there are 6 primary hydrogens and 6secondary hydrogens and the fact that they react at the samerate...but it's wrong...
Explanation / Answer
Given that 1-chloropentane is 16%, the remaining 6 hydrogens have atotal of 84%. Therefore each hyrdogen is likely to be chlorinated14% of the time. 4 of the 6 hydrogens will yield 2-chloropentaneand 2 of 6 will yield 3-chloropentane. Therefore, 14%*4 = 56%