Consider a solution prepared from 10g of NaOH in enough water tomake 1 L. 106 kJ

Question

Consider a solution prepared from 10g of NaOH in enough water tomake 1 L. 106 kJ of heat is evolved.

1) What is q for the dissolving of 2.50g of NaOH to a total volumeof 1 L? ansr(-26.5 kJ)


2) What is q for the dissolving of one mole of NaOH? ansr(-424kJ)



I need help arriving to those answers and how to do them please. Ihope you can help me


Complete and balance the following chemical equations if a reactionoccurs. If no reaction occurs, write "No reaction".

I- (aq) + Cl2 (aq) ->

Br- (aq) + I2 (aq) ->

I really need help please. How do i write the equation and how totell if one forms or not? Is it realted to net equations?

Explanation / Answer

Consider a solution prepared from 10g of NaOH in enough waterto make 1 L. 106 kJ of heat is evolved.
so for 10 g of NaOH we need q = 106 KJ
here for part 1) for 2.5 g NaOH we need to have q = (106/10)*2.5 KJ                                                      = 26.5 KJ here it follows the simple unitary method and as heat isevolved so we give minus sign as convention so we need q = -26.5 KJ for part 2) here 1 mole of NaOH is given i.e = 23+ 16+ 1                                                  = 40 g so for 40 g of NaOH we need q = (106/10)*40 KJ                                                   = -424 KJ(- sign as heat evolved) now second part of question: here we know that in electrochemical series we have first F,then Br, Then Cl, then I. so as lower one in electrochemical series cant replace theupper ones so here I cant replace Br and Br cant replace Cl.
2I- (aq) + Cl2 (aq) ->I2 + 2Cl-

Br- (aq) + I2 (aq) -> no reaction as here I cannot replaceCl
                                                  =

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