I have parts 1 and 2 i just need help with number 3 thank you. The enthalpy chan
ID: 695235 • Letter: I
Question
I have parts 1 and 2 i just need help with number 3 thank you.
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess’s law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize.
Part 1 (1 point)
Part 2 (1 point)
Combine the following equations to determine the enthalpy change for the combustion of 1 mole of propane. Assume that solid carbon is graphite.
Part 3 (1 point)
3C(s,graphite)+4H2(g)C3H8(g)
Ho = -103.8 kJ/molExplanation / Answer
Part 3
According to your given information 1 mole of propane release energy = -2219.9 KJ
15 Kg = 15000 gm
molar mass of propane = 44.1 gm/mole
then 15000 gm = 15000 / 44.1 = 340.136 mole
1 mole of propane release energy = -2219.9 KJ then
340.136 mole of propane release energy = -2219.9 X 340.136 = -755068 KJ
15.00 Kg of propane release energy = -755068 KJ