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I have parts 1 and 2 i just need help with number 3 thank you. The enthalpy chan

ID: 695235 • Letter: I

Question

I have parts 1 and 2 i just need help with number 3 thank you.

The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess’s law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize.

Part 1   (1 point)

Part 2   (1 point)

Combine the following equations to determine the enthalpy change for the combustion of 1 mole of propane. Assume that solid carbon is graphite.

Part 3   (1 point)

3C(s,graphite)+4H2(g)C3H8(g)

Ho = -103.8 kJ/mol

Explanation / Answer

Part 3

According to your given information 1 mole of propane release energy = -2219.9 KJ

15 Kg = 15000 gm

molar mass of propane = 44.1 gm/mole

then 15000 gm = 15000 / 44.1 = 340.136 mole

1 mole of propane release energy = -2219.9 KJ then

340.136 mole of propane release energy = -2219.9 X 340.136 = -755068 KJ

15.00 Kg of propane release energy = -755068 KJ