Part A H for the following reaction N2( g )+2O2( g )2NO2( g ) Express your answe

Question

Part A

H for the following reaction
N2(g)+2O2(g)2NO2(g)

Express your answer using one decimal place.

Part B

S for this reaction.

Express your answer using one decimal place.

Part C

From the values of H and S, calculate G at 25 C.

Express your answer using one decimal place.

Part D

Predict whether this reaction is spontaneous under standard-state conditions.

nonspontaneous under standard-state conditions

Part E

H for the following reaction
2KClO3(s)2KCl(s)+3O2(g)

Express your answer using one decimal place.

Part F

S for this reaction.

Express your answer using one decimal place.

Part G

From the values of H and S, calculate G at 25 C.

Express your answer using one decimal place.

Part H

Predict whether this reaction is spontaneous under standard-state conditions.

nonspontaneous under standard-state conditions

Part I

H for the following reaction
CH3CH2OH(l)+O2(g)CH3CO2H(l)+H2O(l)

Express your answer using one decimal place.

Part J

S for this reaction.

Express your answer using one decimal place.

Part K

From the values of H and S, calculate G at 25 C.

Express your answer using one decimal place.

spontaneous under standard-state conditions

nonspontaneous under standard-state conditions

Part E

H for the following reaction
2KClO3(s)2KCl(s)+3O2(g)

Express your answer using one decimal place.

Part F

S for this reaction.

Express your answer using one decimal place.

Part G

From the values of H and S, calculate G at 25 C.

Express your answer using one decimal place.

Part H

Predict whether this reaction is spontaneous under standard-state conditions.

spontaneous under standard-state conditions

nonspontaneous under standard-state conditions

Part I

H for the following reaction
CH3CH2OH(l)+O2(g)CH3CO2H(l)+H2O(l)

Express your answer using one decimal place.

Part J

S for this reaction.

Express your answer using one decimal place.

Part K

From the values of H and S, calculate G at 25 C.

Express your answer using one decimal place.

Explanation / Answer

Part A:

N2(g)+2O2(g)2NO2(g)

delta Hrxn = delta Hf of products - delta Hf of reactants

delta Hrxn = (2*delta Hf of NO2) - (2*delta Hf of O2 + delta Hf of N2)

delta Hrxn = (2*33.2) - ( 2*0 +0)

delta Hrxn = 66.4 KJ

Part B

delta Srxn = delta S of products - delta S of reactants

delta Srxn = (2*delta S of NO2) - (2*delta S of O2 + delta S of N2)

delta Srxn = (2*239.7) - (2*205 + 191.6)

delta Srxn = -122.2 J

Part C:

delta G = delta H - T*delta S

T in kelvin = 25C = 298 K

delta G = 66.4 KJ + (298*-122.2)

delta G = 29.9844 KJ

when delta G is negative , the reaction is spontaneous

Since delta G is positive here , the reaction is non spontaneous

similarly for otherbelow problems

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