Part A) Binding energy for 19F it has 9 protons and 10 neutrons mass defect = (9
ID: 699553 • Letter: P
Question
Part A) Binding energy for 19F
it has 9 protons and 10 neutrons
mass defect = (9 x 1.007825 + 10 x 1.008665) - 19 = 0.157075 amu
mass in kg = 0.157075 x 1.66054 x 10^-27 = 2.61 x 10^-28 kg
Binding energy = mc^2 = (2.61 x 10^-28)(2.998 x 10^8)^2 = 2.346 x 10^-11 J
Given, 1 eV = 1.602 x 10^-19 J
Binding energy (MeV) = 2.346 x 10^-11/1.602 x 10^-19 x 10^6 = 1.464 x 10^8 MeV
Part C) Binding energy per nucleon
nucleon = 19
Binding energy (MeV/nucleon) = 1.464 x 10^8/19 = 7.70 x 10^6 MeV/nucleon
Part D) mass defect of 4He(2)
mass defect = (2 x 1.007825 + 2 x 1.008665) - 4.002603 = 0.030377 amu
Part E) Binding energy for He
= (0.030377 x 1.66054 x 10^-27)(2.998 x 10^8)^2/1.602 x 10^-19 x 10^6 = 2.83 x 10^4 MeV
Part F) binding energy per nucleon for He = 2.83 x 10^4/4 = 7075 MeV/nucleon
Explanation / Answer
Nucleons
The term nucleon refers to the particles found in the nucleus of an atom, namely protons and neutrons. A single hydrogen atom (one proton plus one electron) has a mass of 1.007825 amu. A single neutron has a mass of 1.008665 amu. Note that amu stands for "atomic mass unit" and is sometimes abbreviated with the symbol u. 1 u is equivalent to 1.6605387×1027 kg.
Mass Defect
The total mass of the individual nucleons in an atom is always greater than the actual measured mass of the atom. The difference is called the mass defect.
Binding Energy
The mass defect of an atom corresponds to an amount of energy called the binding energy. Binding energy can be calculated using Einstein's equation, E=mc2., where E is energy in joules, m is mass is kilograms, and c is the speed of light, 2.998×108 m/s.
Part B) Calculate the binding energy E of the fluorine nucleus 19 9F (1eV=1.602×1019J). (in MeV)
Part C) Calculate the binding energy per nucleon of the fluorine nucleus 19 9F. (in Me V/ nucleon)
Part D) Calculate the mass defect of the helium nucleus 42He. The mass of neutral 42He is given by MHe=4.002603amu.
Part E) Calculate the binding energy E of the helium nucleus 42He (1eV=1.602×1019J).
Part F) Calculate the binding energy per nucleon of the helium nucleus 42He.