Topic: nucleotide Can someone please help me answer the questions above and expl

Question

Topic: nucleotide

Can someone please help me answer the questions above and explain why did you pick that answer?

Thanks

Which of the following statement best. explains why DNA Polymerase I can remove the RNA primer from Okazaki fragments and DNA Polymerase III cannot? because Pol III lacks the 5 rightarrow 3' exonuclease that Pol I contains because Pol III is not a very processive polymerase, while Po because Pol I is not a very processive polymerase while because Pol III lacks the 3'rightarrow 5' exonuclease that Pol I contain E because Pol I contains a 3rightarrow5' exonuclease that Pol II contains

Explanation / Answer

A. because Pol II lacks the 5' -3' exonuclease that Pol I contains.

Explanation:-

Prokaryotic Family A polymerases include the DNA polymerase I (Pol I) enzyme, which is encoded by the polA gene and ubiquitous among prokaryotes. This repair polymerase is involved in excision repair with 3'-5' and 5'-3' exonuclease activity and processing ofOkazaki fragments generated during lagging strand synthesis. Pol I is the most abundant polymerase accounting for >95% of polymerase activity in E. coli, yet cells lacking Pol I have been found suggesting Pol I activity can be replaced by the other four polymerases. Pol I adds ~15-20 nucleotides per second, thus showing poor processivity. Instead, Pol I starts adding nucleotides at the RNA primer:template junction known as the origin of replication.

RNA primers are the start of the leading strand and also in between the Okazaki fragments on the lagging strand. This is where DNA polymerase I comes in. DNA polymerase I has a 5'-3' exonuclease that chews up the RNA primer so that it can replace the RNA with DNA. Once it has done this ligase comes in to seal the nick.

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