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Indicators Phenolphthalein is a commonly used indicator that is colorless in the

ID: 705165 • Letter: I

Question

Indicators Phenolphthalein is a commonly used indicator that is colorless in the acidic form (pH 10.0). It is a weak acid with a pKa of 8.7. What is the ratio of the conjugate base concentration to the acid concentration, that is, [B-???] when the indicator switches to the acidic color? Hint given in feedback. Answer: Use the result to the above question to determine what percent is in the acidic form when the acid color is first apparent? Answer: What is [B VHB] when the indicator switches to the basic color? Answer: Use the result to the above question to determine what percent is in the basic form when the base color is first apparent Answer:

Explanation / Answer

The pka of phenolpthalein =8.7

pka=-log Ka , where Ka=acid dissociation constant of weak acid like phenolpthalein(say of the form HB)

HB <--->B-+H+ , ka=equilibrium constant=[B-][H+]/[HB]

HB form or acidic form of phenolpthalein is colorless,B- or basic form is pink

1) Using Henderson-hasselbach equation,

pH=pka +log [B-]/[HB]

It switches to acidic color at pH<8.3,

8.3=8.7+log [B-]/[HB]

or, log [B-]/[HB]=8.2-8.7=-0.4

or, [B-]/[HB]=10^-0.4=0.398

[B-]/[HB]=0.398

2) [B-]/[HB]=0.398

Add 1 to both sides,

[B-]/[HB]+1=0.398+1

or, [B-]+[HB]/[HB]=1.398

or,taking inverse of both sides,

[HB]/([B-]+[HB])=1/1.398

or, acid concentration/total concentration of acid and conjugate base=[HB]/([B-]+[HB])=0.715

percent acid=100*0.760=71.5%

3)Base color is first apparant at pH>10.0

Using Henderson-hasselbach equation,

pH=pka +log [B-]/[HB]

10.0=8.7+log [B-]/[HB]

or, log [B-]/[HB]=10.0-8.7=1.3

or, [B-]/[HB]=10^1.3=19.952

[B-]/[HB]=19.952

2) [B-]/[HB]=19.952

taking inverse of both sides,

[HB]/[B-]=1/19.952=0.0501

Add 1 to both sides,

[HB]/[B-]+1=0.0501+1

or, [B-]+[HB]/[B-]=1.0501

or,taking inverse of both sides,

[B-]/([B-]+[HB])=1/1.0501=0.952

or, base concentration/total concentration of acid and conjugate base=[B]/([B-]+[HB])=0.952

percent acid=100*0.952=95.2%

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