Consider the equilibrium below at 25 ºC in which H = 42 kJ and K c = 23.4. Which
ID: 712556 • Letter: C
Question
Consider the equilibrium below at 25 ºC in which H = 42 kJ and Kc = 23.4. Which best describes what happens if the volume of the container is increased?
C (s) + H2O (g) CO (g) + H2 (g)
Question 14 options:
The reaction shifts to the right.
K decreases.
K increases.
The reaction shifts to the right and K increases.
The reaction shifts to the left and K decreases.
PLEASE EXPLAIN HOW YOU WENT ABOUT THE ANSWER STEP BY STEP. Thanks!
The reaction shifts to the right.
K decreases.
K increases.
The reaction shifts to the right and K increases.
The reaction shifts to the left and K decreases.
PLEASE EXPLAIN HOW YOU WENT ABOUT THE ANSWER STEP BY STEP. Thanks!
Explanation / Answer
answer : The reaction shifts to the right.
moles of reactants = 1
moles of products =1 + 1 = 2
if volume increases reaction shifts to moles increases side.
so 1-------------> 2 moles increase side . so shift towards forward direction
note that on increase in volume it doesnot effect the K value. K value only depends on temperature . so the answers which involved K term all are wrong