CH3OH ?9? Br CH3 Look at the given reaction and use the letter code correspondin
ID: 712802 • Letter: C
Question
CH3OH ?9? Br CH3 Look at the given reaction and use the letter code corresponding to each compound in the blank to indicate the expected product(s) or correct vocabulary word/phrase to complete the description. If a specific stereoisomer (e.g single enantiomer) is formed, select that isomer only. If a mixture of stereoisomers (e.g. racemic or diastereomers) is formed, select the single structure that shows the appropriate mixture (e.g. lines not dashes). This reaction will form compound as the only substance. If we convert the nucleophile to CH3O the major product will become compound by a(n) by a(n) mechanism and the minor product will be compound mechanismExplanation / Answer
The reaction will form compound F as the only substance.(as methanol is weak nucleophile and the substrate is primary unhindered halo alkane.)
If we convert the nucleophile to CH3O- the maajor product will become compound C by a E2 mechanism(as methoxide is a strong base and good nucleophile) and the minor product D/H will be compound by E1 mechanism.(carbocation will rearrange)