In a combustion analysis, a 1.054-g sample of maleic acid yields 1.599g of CO29
ID: 729334 • Letter: I
Question
In a combustion analysis, a 1.054-g sample of maleic acid yields 1.599g of CO29 and 0.327g of H20.When 0.609g of maleic acid dissolved in 25.00g of glacial acetic acid, the freezing point drops by 0.82 degrees C Maleic acid does not ionize in glacial acedic acid, which has a freezing point depression constant of Kf=3.90*c/m.
In a titration experiment, a 0.4250-g sample of maleic acid is dissolved in water and requires 34.03ml of 0.2152 M KOH for its complete neutralization.
The pH of 0.215g of maleic acid in 50.00mL of aqueous solution is found to be 1.80.
(Part A)
Determine the empirical formula for maleic acid. Enter the atoms in order of C, H, and O.
Please explain in detail! Thanks!
Explanation / Answer
a 1.054-g sample of maleic acid yields 1.599g of CO2 and 0.327g of H2O so find mass using molar masses 1.599g of CO2 @ (12.01 g Carbon) / (44.01 g CO2) = 0.436 grams of Carbon 0.327g of H2O @ (2.016 g Hydrogen) / (18.01 g/mol H2O) = 0.037 grams of Hydrogen 1.054-g sample - 0.436 grams of Carbon - 0.037 grams of Hydrogen = 0.581 grams of oxygen now use molar masses to find moles 0.436 grams of Carbon @ 12.01 g/mol = 0.0363 mol C 0.037 grams of Hydrogen @ 1.008 g/mol = 0.0367 mol H 0.581 grams of oxygen @ 16.00 g/mol = 0.0363 mol O your empirical formula is CHO