A sample of N2O3 (g) has a pressure of 0.017 atm. The temperature of (in K) is t
ID: 739591 • Letter: A
Question
A sample of N2O3 (g) has a pressure of 0.017 atm. The temperature of (in K) is then doubled and the N2O3 undergoes complete decomposition to NO2 (g) and NO (g). Find the total pressure of the mixture of gases assuming constant volume and no additional temperature change.
Explanation / Answer
N2O3 -> NO2 + NO With constant volume, doubling of temperature results in a doubling of the pressure. 0.017atm * 2 = 0.034atm When N2O3 decomposes into NO2 and NO, the pressure is kept the same per mole but since there are now one mole of NO2 and one mole of NO, the pressure is 0.034atm + 0.034atm or 0.068atm