I. Sulfuric acid reacts with water to yield hydrogen sulfate ions and hydronium

Question

I. Sulfuric acid reacts with water to yield hydrogen sulfate ions and hydronium ions:

H2SO4+H2O?HSO4?+H3O+

Identify the conjugate acid-base pairs.

Drag each item to the appropriate bin.

II. Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions:

HSO4-+H2O?SO42?+H3O+

Identify the conjugate acid-base pairs.

Drag each item to the appropriate bin.

I. Sulfuric acid reacts with water to yield hydrogen sulfate ions and hydronium ions: H2SO4+H2O?HSO4?+H3O+ Identify the conjugate acid-base pairs. Drag each item to the appropriate bin. II. Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: HSO4-+H2O?SO42?+H3O+ Identify the conjugate acid-base pairs. Drag each item to the appropriate bin.

Explanation / Answer

we know that

to get a conjugate base , H+ should be removed

and

to get a conjugate acid , H+ should be added

1) consider the given reaction

H2S04 + H20 ---> HS04- + H30+

we know that

H2S04 is a strong acid

now

to get its conjugate base , H+ should be removed

so

its conjugate base is HS04-

now

in the given reaction H2S04 acts as an acid

so

H20 is the base

now

to get its conjugate acid , H+ should be added

so

H30+ is the conjugate acid of H20

so

finally

Acid ---> H2S04

conjugate base ---> Hs04-

Base ----> H20

conjugate acid ----> H30+

2)

consider the given reaction

HS04- + H20 ---> S042- + H20

in this case

Hs04- donates a H+ to H20 to become S042-

so

we know that H+ donors are acids

and

H+ acceptors are bases

so

HS04- is acid and H20 is the base

now

to get conjugate base of HS04- , remove H+

so

S042- is the conjugate base of HS04-

now

to get the conjugate acid of H20 , add H+

so

H30+ is the conjugate acid is H30+

finally

Acid ---> HS04-

conjugate base ----> S042-

Base ---> H20

conjugate acid ---> H30+

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---