Three gases (8.00 g of methane, C H 4 , 18.0 g of ethane, C 2 H 6 , and an unkno
ID: 789091 • Letter: T
Question
Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 3.60atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane. Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 3.60atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.Explanation / Answer
Pv=nRT
3.6*10=n*0.0821*(273+23)
n=total no. of moles=1.4864 moles
no. of moles of methane=8/16=0.5
no. of moles of ethane=18/30=0.533
no. of moles of propane=1.4843-0.5-0.533=0.4534 moles
partial pressure of methane= mole fraction of methane*total pressure=0.5*3.6/1.4864=1.21 atm
partial pressure of ethane= mole fraction of ethane*total pressure=0.533*3.6/1.4864=1.29 atm
partial pressure of propane= mole fraction of propane*total pressure=0.4534*3.6/1.4864=1.098 atm