Three gases (8.00 g of methane, C H 4 , 18.0 g of ethane, C 2 H 6 , and an unkno
ID: 823009 • Letter: T
Question
Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 4.10atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane. Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 4.10atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.Explanation / Answer
PV = nRT
4.1*10 = n*0.0821*300
n = 41/0.0821*300 = 1.66 moles
moles of methane = 8/16 = 0.5 moles
moles of ethane = 18/30 = 0.6 moles
moles of propane = 1.66-0.5-0.6 = 0.56 moles
Mole fraction of methane = 0.5/1.66*4.10 = 1.23 atm
Mole fraction of ethane= 0.6/1.66*4.10 = 1.48 atm
Mole fraction of methane = 0.56/1.66*4.10 = 1.38 atm