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Three gases (8.00 g of methane, C H 4 , 18.0 g of ethane, C 2 H 6 , and an unkno

ID: 823009 • Letter: T

Question

Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 4.10atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane. Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 ?C, the total pressure in the container is 4.10atm . Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.

Explanation / Answer

PV = nRT

4.1*10 = n*0.0821*300

n = 41/0.0821*300 = 1.66 moles


moles of methane = 8/16 = 0.5 moles

moles of ethane = 18/30 = 0.6 moles

moles of propane = 1.66-0.5-0.6 = 0.56 moles


Mole fraction of methane = 0.5/1.66*4.10 = 1.23 atm

Mole fraction of ethane= 0.6/1.66*4.10 = 1.48 atm

Mole fraction of methane = 0.56/1.66*4.10 = 1.38 atm