Here\'s a problem I\'m having trouble with. It\'s number 37. Please show how you

Question

Here's a problem I'm having trouble with. It's number 37. Please show how you got the answer (I already know what the answer is, I'm just not sure how to get to that point.)

The general formula for an alkane is CnH2n-2 CnH2n CnH4n+2 CnH2n+2 Which one of the following elements is diatomic? neon phosphorus iodine calcium The rate law for a particular reaction is Rate = K[A]2[B]. If for a particular run of this reaction, the concentration of A were doubled over what it had been in the previous run, while the concentration of B were halved, what would be the effect on the rate? The rate would decrease by a factor of two. The rate would double. The rate would remain the same. The rate would quadruple. I2(g) + H2(g) doubldheadarrow 2HI(g) At equilibrium the following conentrations are measured:

Explanation / Answer

Well,K is constant.
so R is directly proportional to the SQUARE of the concentration of A and also directly proportional to the concentration of B.

Hence let initial rate be R1 = k [A]^2 [B]

concetraion of A in second case = 2*[A]

for B, = [B]/2

substituing this we get,final rate,R2 = k* ( 2[A] ) ^2 ( [B]/2 ) = 2*(k*[A]^2 [B] ) = 2*R1

hence the rate would double.

Answer B.
Hope this helps :)

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