Consider the following reaction in a closed reaction flask. If 1.00 atm of gas A
ID: 794848 • Letter: C
Question
Consider the following reaction in a closed reaction flask. If 1.00 atm of gas A is allowed to react with 1.00 atm of gas B and the reaction goes to completion at constant temperature and volume, what is the total pressure in the reaction flask at the end of the reaction? What are the partial pressures of the gases in the flask?
6A(g) + 2B(g) ? 2A3B(g)
A. (0.667 atm of A3B produced) + (0.333 atm of B remaining) = 1.00 atm total pressure B. (1.00 atm of A3B produced) + (0.333 atm of A remaining) = 1.33 atm total pressure C. (0.333 atm of A3B produced) + (0.167 atm of A remaining) = 0.500 atm total pressure D. (0.333 atm of A3B produced) + (0.667 atm of B remaining) = 1.00 atm total pressureExplanation / Answer
6A(g) + 2B(g) ? 2A3B(g)
for 1mole of A 1/3 of B is required then 2/3 of product forms
so
D. (0.333 atm of A3B produced) + (0.667 atm of B remaining) = 1.00 atm total pressure