An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of
ID: 796150 • Letter: A
Question
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates.Calculate the new partial pressures after equilibrium is reestablished.
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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates.
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates.
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates.
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
Calculate the new partial pressures after equilibrium is reestablished.
I will rate 5 and best answer!
Explanation / Answer
PCl3(g) + Cl2(g) <-> PCl5(g)
13.2 13.2 217 sum = 243.4
Now, Cl2 is added to the system. The amount added is 263 - 243.4 = 19.6
The following is now the case:
13.2 - x 13.2 + 19.6 217 + x
= 32.8
Adding the Cl2 perturbs the system and according to LeChatiliers principle the equillibrium increases to the right to compensate. Note however since there is no change in equillibrium constant (since there is no temperature change) the following relationship exists:
(217)/((13.2) x (13.2)) + (217 + x)/((32.8) x (13.2 -x))
This reduces to 40.849 = (217 + x)/(13.2 - x) then x = 7
Plug the x value in and you get thenew values:
PCl3(g) + Cl2(g) <-> PCl5(g)
6.2 32.8 224 sum = 263